This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
9∙163+14∙162+3∙161+6∙160+7∙16-1+10∙16-2 = 9∙4096+14∙256+3∙16+6∙1+7∙0.0625+10∙0.00390625 = 36864+3584+48+6+0.4375+0.0390625 = 40502.476562510
got It: 9E36.7A16 =40502.476562510
Translate the number 40502.476562510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
40502 | 8 | | | | | |
-40496 | 5062 | 8 | | | | |
6 | -5056 | 632 | 8 | | | |
| 6 | -632 | 79 | 8 | | |
| | 0 | -72 | 9 | 8 | |
| | | 7 | -8 | 1 | |
| | | | 1 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 4765625*8 |
3 | .8125*8 |
6 | .5*8 |
4 | .0*8 |
the result of the conversion was:
40502.476562510 = 117066.3648
answer: 9E36.7A16 = 117066.3648
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
9E36.7A16 = 9 E 3 6. 7 A = 9(=1001) E(=1110) 3(=0011) 6(=0110). 7(=0111) A(=1010) = 1001111000110110.01111012
answer: 9E36.7A16 = 1001111000110110.01111012
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001001111000110110.0111101002 = 001 001 111 000 110 110. 011 110 100 = 001(=1) 001(=1) 111(=7) 000(=0) 110(=6) 110(=6). 011(=3) 110(=6) 100(=4) = 117066.3648
answer: 9E36.7A16 = 117066.3648