This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
1∙82+2∙81+5∙80 = 1∙64+2∙8+5∙1 = 64+16+5 = 8510
got It: 1258 =8510
Translate the number 8510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
85 | 16 | |
-80 | 5 | |
5 | | |
|
the result of the conversion was:
8510 = 5516
answer: 1258 = 5516
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
1258 = 1 2 5 = 1(=001) 2(=010) 5(=101) = 0010101012
answer: 1258 = 10101012
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
010101012 = 0101 0101 = 0101(=5) 0101(=5) = 5516
answer: 010101018 = 5516