This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
9∙161+15∙160+10∙16-1+11∙16-2 = 9∙16+15∙1+10∙0.0625+11∙0.00390625 = 144+15+0.625+0.04296875 = 159.6679687510
got It: 9F.AB16 =159.6679687510
Translate the number 159.6679687510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
159 | 8 | | |
-152 | 19 | 8 | |
7 | -16 | 2 | |
| 3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 66796875*8 |
5 | .34375*8 |
2 | .75*8 |
6 | .0*8 |
the result of the conversion was:
159.6679687510 = 237.5268
answer: 9F.AB16 = 237.5268
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
9F.AB16 = 9 F. A B = 9(=1001) F(=1111). A(=1010) B(=1011) = 10011111.101010112
answer: 9F.AB16 = 10011111.101010112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
010011111.1010101102 = 010 011 111. 101 010 110 = 010(=2) 011(=3) 111(=7). 101(=5) 010(=2) 110(=6) = 237.5268
answer: 9F.AB16 = 237.5268