This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
1∙162+10∙161+13∙160+14∙16-1+0∙16-2 = 1∙256+10∙16+13∙1+14∙0.0625+0∙0.00390625 = 256+160+13+0.875+0 = 429.87510
got It: 1AD.E016 =429.87510
Translate the number 429.87510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
429 | 8 | | |
-424 | 53 | 8 | |
5 | -48 | 6 | |
| 5 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 875*8 |
7 | .0*8 |
the result of the conversion was:
429.87510 = 655.78
answer: 1AD.E016 = 655.78
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
1AD.E016 = 1 A D. E 0 = 1(=0001) A(=1010) D(=1101). E(=1110) 0(=0000) = 110101101.1112
answer: 1AD.E016 = 110101101.1112
let\'s make a direct translation from binary to post-binary like this:
110101101.1112 = 110 101 101. 111 = 110(=6) 101(=5) 101(=5). 111(=7) = 655.78
answer: 1AD.E016 = 655.78