This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
10∙162+2∙161+4∙160+12∙16-1+0∙16-2+9∙16-3 = 10∙256+2∙16+4∙1+12∙0.0625+0∙0.00390625+9∙0.000244140625 = 2560+32+4+0.75+0+0.002197265625 = 2596.75219726562510
got It: A24.C0916 =2596.75219726562510
Translate the number 2596.75219726562510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
2596 | 8 | | | |
-2592 | 324 | 8 | | |
4 | -320 | 40 | 8 | |
| 4 | -40 | 5 | |
| | 0 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 752197265625*8 |
6 | .01758*8 |
0 | .14063*8 |
1 | .125*8 |
1 | .0*8 |
the result of the conversion was:
2596.75219726562510 = 5044.60118
answer: A24.C0916 = 5044.60118
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
A24.C0916 = A 2 4. C 0 9 = A(=1010) 2(=0010) 4(=0100). C(=1100) 0(=0000) 9(=1001) = 101000100100.1100000010012
answer: A24.C0916 = 101000100100.1100000010012
let\'s make a direct translation from binary to post-binary like this:
101000100100.1100000010012 = 101 000 100 100. 110 000 001 001 = 101(=5) 000(=0) 100(=4) 100(=4). 110(=6) 000(=0) 001(=1) 001(=1) = 5044.60118
answer: A24.C0916 = 5044.60118