This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
b316 = b 3 = b(=1011) 3(=0011) = 101100112
answer: b316 = 101100112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
11∙161+3∙160 = 11∙16+3∙1 = 176+3 = 17910
got It: b316 =17910
Translate the number 17910 в binary like this:
the Integer part of the number is divided by the base of the new number system:
179 | 2 | | | | | | | |
-178 | 89 | 2 | | | | | | |
1 | -88 | 44 | 2 | | | | | |
| 1 | -44 | 22 | 2 | | | | |
| | 0 | -22 | 11 | 2 | | | |
| | | 0 | -10 | 5 | 2 | | |
| | | | 1 | -4 | 2 | 2 | |
| | | | | 1 | -2 | 1 | |
| | | | | | 0 | | |
|
the result of the conversion was:
17910 = 101100112
answer: b316 = 101100112