This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
0∙169+11∙168+1∙167+1∙166+1∙165+1∙164+1∙163+1∙162+1∙161+1∙160 = 0∙68719476736+11∙4294967296+1∙268435456+1∙16777216+1∙1048576+1∙65536+1∙4096+1∙256+1∙16+1∙1 = 0+47244640256+268435456+16777216+1048576+65536+4096+256+16+1 = 4753097140910
got It: 0b1111111116 =4753097140910
Translate the number 4753097140910 в octal like this:
the Integer part of the number is divided by the base of the new number system:
47530971409 | 8 | | | | | | | | | | | |
-47530971408 | 5941371426 | 8 | | | | | | | | | | |
1 | -5941371424 | 742671428 | 8 | | | | | | | | | |
| 2 | -742671424 | 92833928 | 8 | | | | | | | | |
| | 4 | -92833928 | 11604241 | 8 | | | | | | | |
| | | 0 | -11604240 | 1450530 | 8 | | | | | | |
| | | | 1 | -1450528 | 181316 | 8 | | | | | |
| | | | | 2 | -181312 | 22664 | 8 | | | | |
| | | | | | 4 | -22664 | 2833 | 8 | | | |
| | | | | | | 0 | -2832 | 354 | 8 | | |
| | | | | | | | 1 | -352 | 44 | 8 | |
| | | | | | | | | 2 | -40 | 5 | |
| | | | | | | | | | 4 | | |
|
the result of the conversion was:
4753097140910 = 5421042104218
answer: 0b1111111116 = 5421042104218
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
0b1111111116 = 0 b 1 1 1 1 1 1 1 1 = 0(=0000) b(=1011) 1(=0001) 1(=0001) 1(=0001) 1(=0001) 1(=0001) 1(=0001) 1(=0001) 1(=0001) = 1011000100010001000100010001000100012
answer: 0b1111111116 = 1011000100010001000100010001000100012
let\'s make a direct translation from binary to post-binary like this:
1011000100010001000100010001000100012 = 101 100 010 001 000 100 010 001 000 100 010 001 = 101(=5) 100(=4) 010(=2) 001(=1) 000(=0) 100(=4) 010(=2) 001(=1) 000(=0) 100(=4) 010(=2) 001(=1) = 5421042104218
answer: 0b1111111116 = 5421042104218