This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
60378 = 6 0 3 7 = 6(=110) 0(=000) 3(=011) 7(=111) = 1100000111112
answer: 60378 = 1100000111112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
6∙83+0∙82+3∙81+7∙80 = 6∙512+0∙64+3∙8+7∙1 = 3072+0+24+7 = 310310
got It: 60378 =310310
Translate the number 310310 в binary like this:
the Integer part of the number is divided by the base of the new number system:
3103 | 2 | | | | | | | | | | | |
-3102 | 1551 | 2 | | | | | | | | | | |
1 | -1550 | 775 | 2 | | | | | | | | | |
| 1 | -774 | 387 | 2 | | | | | | | | |
| | 1 | -386 | 193 | 2 | | | | | | | |
| | | 1 | -192 | 96 | 2 | | | | | | |
| | | | 1 | -96 | 48 | 2 | | | | | |
| | | | | 0 | -48 | 24 | 2 | | | | |
| | | | | | 0 | -24 | 12 | 2 | | | |
| | | | | | | 0 | -12 | 6 | 2 | | |
| | | | | | | | 0 | -6 | 3 | 2 | |
| | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | 1 | | |
|
the result of the conversion was:
310310 = 1100000111112
answer: 60378 = 1100000111112