This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0010100111110001012 = 001 010 011 111 000 101 = 001(=1) 010(=2) 011(=3) 111(=7) 000(=0) 101(=5) = 1237058
answer: 10100111110001012 = 1237058
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙217+0∙216+1∙215+0∙214+1∙213+0∙212+0∙211+1∙210+1∙29+1∙28+1∙27+1∙26+0∙25+0∙24+0∙23+1∙22+0∙21+1∙20 = 0∙131072+0∙65536+1∙32768+0∙16384+1∙8192+0∙4096+0∙2048+1∙1024+1∙512+1∙256+1∙128+1∙64+0∙32+0∙16+0∙8+1∙4+0∙2+1∙1 = 0+0+32768+0+8192+0+0+1024+512+256+128+64+0+0+0+4+0+1 = 4294910
got It: 0010100111110001012 =4294910
Translate the number 4294910 в octal like this:
the Integer part of the number is divided by the base of the new number system:
42949 | 8 | | | | | |
-42944 | 5368 | 8 | | | | |
5 | -5368 | 671 | 8 | | | |
| 0 | -664 | 83 | 8 | | |
| | 7 | -80 | 10 | 8 | |
| | | 3 | -8 | 1 | |
| | | | 2 | | |
|
the result of the conversion was:
4294910 = 1237058
answer: 10100111110001012 = 1237058