This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
011010111.1100002 = 011 010 111. 110 000 = 011(=3) 010(=2) 111(=7). 110(=6) 000(=0) = 327.608
answer: 11010111.11002 = 327.608
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+1∙26+0∙25+1∙24+0∙23+1∙22+1∙21+1∙20+1∙2-1+1∙2-2+0∙2-3+0∙2-4+0∙2-5+0∙2-6 = 0∙256+1∙128+1∙64+0∙32+1∙16+0∙8+1∙4+1∙2+1∙1+1∙0.5+1∙0.25+0∙0.125+0∙0.0625+0∙0.03125+0∙0.015625 = 0+128+64+0+16+0+4+2+1+0.5+0.25+0+0+0+0 = 215.7510
got It: 011010111.1100002 =215.7510
Translate the number 215.7510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
215 | 8 | | |
-208 | 26 | 8 | |
7 | -24 | 3 | |
| 2 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 75*8 |
6 | .0*8 |
the result of the conversion was:
215.7510 = 327.68
answer: 11010111.11002 = 327.68