This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
10∙162+11∙161+12∙160+3∙16-1+13∙16-2+12∙16-3 = 10∙256+11∙16+12∙1+3∙0.0625+13∙0.00390625+12∙0.000244140625 = 2560+176+12+0.1875+0.05078125+0.0029296875 = 2748.241210937510
got It: ABC.3DC16 =2748.241210937510
Translate the number 2748.241210937510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
2748 | 8 | | | |
-2744 | 343 | 8 | | |
4 | -336 | 42 | 8 | |
| 7 | -40 | 5 | |
| | 2 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 2412109375*8 |
1 | .92969*8 |
7 | .4375*8 |
3 | .5*8 |
4 | .0*8 |
the result of the conversion was:
2748.241210937510 = 5274.17348
answer: ABC.3DC16 = 5274.17348
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
ABC.3DC16 = A B C. 3 D C = A(=1010) B(=1011) C(=1100). 3(=0011) D(=1101) C(=1100) = 101010111100.00111101112
answer: ABC.3DC16 = 101010111100.00111101112
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
101010111100.0011110111002 = 101 010 111 100. 001 111 011 100 = 101(=5) 010(=2) 111(=7) 100(=4). 001(=1) 111(=7) 011(=3) 100(=4) = 5274.17348
answer: ABC.3DC16 = 5274.17348