This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
15∙160+4∙16-1 = 15∙1+4∙0.0625 = 15+0.25 = 15.2510
got It: F.416 =15.2510
Translate the number 15.2510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
15 | 8 | |
-8 | 1 | |
7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 25*8 |
2 | .0*8 |
the result of the conversion was:
15.2510 = 17.28
answer: F.416 = 17.28
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
F.416 = F. 4 = F(=1111). 4(=0100) = 1111.012
answer: F.416 = 1111.012
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001111.0102 = 001 111. 010 = 001(=1) 111(=7). 010(=2) = 17.28
answer: F.416 = 17.28