This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
10∙162+11∙161+15∙160+2∙16-1+11∙16-2 = 10∙256+11∙16+15∙1+2∙0.0625+11∙0.00390625 = 2560+176+15+0.125+0.04296875 = 2751.1679687510
got It: ABF.2B16 =2751.1679687510
Translate the number 2751.1679687510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
2751 | 8 | | | |
-2744 | 343 | 8 | | |
7 | -336 | 42 | 8 | |
| 7 | -40 | 5 | |
| | 2 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 16796875*8 |
1 | .34375*8 |
2 | .75*8 |
6 | .0*8 |
the result of the conversion was:
2751.1679687510 = 5277.1268
answer: ABF.2B16 = 5277.1268
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
ABF.2B16 = A B F. 2 B = A(=1010) B(=1011) F(=1111). 2(=0010) B(=1011) = 101010111111.001010112
answer: ABF.2B16 = 101010111111.001010112
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
101010111111.0010101102 = 101 010 111 111. 001 010 110 = 101(=5) 010(=2) 111(=7) 111(=7). 001(=1) 010(=2) 110(=6) = 5277.1268
answer: ABF.2B16 = 5277.1268