This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
110.0102 = 110. 010 = 110(=6). 010(=2) = 6.28
answer: 110.012 = 6.28
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙22+1∙21+0∙20+0∙2-1+1∙2-2+0∙2-3 = 1∙4+1∙2+0∙1+0∙0.5+1∙0.25+0∙0.125 = 4+2+0+0+0.25+0 = 6.2510
got It: 110.0102 =6.2510
Translate the number 6.2510 в octal like this:
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 25*8 |
2 | .0*8 |
the result of the conversion was:
6.2510 = 6.28
answer: 110.012 = 6.28