This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
5C9.A16 = 5 C 9. A = 5(=0101) C(=1100) 9(=1001). A(=1010) = 10111001001.1012
answer: 5C9.A16 = 10111001001.1012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
5∙162+12∙161+9∙160+10∙16-1 = 5∙256+12∙16+9∙1+10∙0.0625 = 1280+192+9+0.625 = 1481.62510
got It: 5C9.A16 =1481.62510
Translate the number 1481.62510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
1481 | 2 | | | | | | | | | | |
-1480 | 740 | 2 | | | | | | | | | |
1 | -740 | 370 | 2 | | | | | | | | |
| 0 | -370 | 185 | 2 | | | | | | | |
| | 0 | -184 | 92 | 2 | | | | | | |
| | | 1 | -92 | 46 | 2 | | | | | |
| | | | 0 | -46 | 23 | 2 | | | | |
| | | | | 0 | -22 | 11 | 2 | | | |
| | | | | | 1 | -10 | 5 | 2 | | |
| | | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | 0 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 625*2 |
1 | .25*2 |
0 | .5*2 |
1 | .0*2 |
the result of the conversion was:
1481.62510 = 10111001001.1012
answer: 5C9.A16 = 10111001001.1012