This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
7∙82+5∙81+2∙80 = 7∙64+5∙8+2∙1 = 448+40+2 = 49010
got It: 7528 =49010
Translate the number 49010 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
490 | 16 | | |
-480 | 30 | 16 | |
A | -16 | 1 | |
| E | | |
|
the result of the conversion was:
49010 = 1EA16
the Final answer: 7528 = 1EA16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
7528 = 7 5 2 = 7(=111) 5(=101) 2(=010) = 1111010102
the Final answer: 7528 = 1111010102
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0001111010102 = 0001 1110 1010 = 0001(=1) 1110(=E) 1010(=A) = 1EA16
the Final answer: 0001111010108 = 1EA16