This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
80e16 = 8 0 e = 8(=1000) 0(=0000) e(=1110) = 1000000011102
answer: 80e16 = 1000000011102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
8∙162+0∙161+14∙160 = 8∙256+0∙16+14∙1 = 2048+0+14 = 206210
got It: 80e16 =206210
Translate the number 206210 в binary like this:
the Integer part of the number is divided by the base of the new number system:
2062 | 2 | | | | | | | | | | | |
-2062 | 1031 | 2 | | | | | | | | | | |
0 | -1030 | 515 | 2 | | | | | | | | | |
| 1 | -514 | 257 | 2 | | | | | | | | |
| | 1 | -256 | 128 | 2 | | | | | | | |
| | | 1 | -128 | 64 | 2 | | | | | | |
| | | | 0 | -64 | 32 | 2 | | | | | |
| | | | | 0 | -32 | 16 | 2 | | | | |
| | | | | | 0 | -16 | 8 | 2 | | | |
| | | | | | | 0 | -8 | 4 | 2 | | |
| | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | 0 | | |
|
the result of the conversion was:
206210 = 1000000011102
answer: 80e16 = 1000000011102