This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011000111011102 = 001 100 011 101 110 = 001(=1) 100(=4) 011(=3) 101(=5) 110(=6) = 143568
answer: 11000111011102 = 143568
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙214+0∙213+1∙212+1∙211+0∙210+0∙29+0∙28+1∙27+1∙26+1∙25+0∙24+1∙23+1∙22+1∙21+0∙20 = 0∙16384+0∙8192+1∙4096+1∙2048+0∙1024+0∙512+0∙256+1∙128+1∙64+1∙32+0∙16+1∙8+1∙4+1∙2+0∙1 = 0+0+4096+2048+0+0+0+128+64+32+0+8+4+2+0 = 638210
got It: 0011000111011102 =638210
Translate the number 638210 в octal like this:
the Integer part of the number is divided by the base of the new number system:
6382 | 8 | | | | |
-6376 | 797 | 8 | | | |
6 | -792 | 99 | 8 | | |
| 5 | -96 | 12 | 8 | |
| | 3 | -8 | 1 | |
| | | 4 | | |
|
the result of the conversion was:
638210 = 143568
answer: 11000111011102 = 143568