This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
1∙162+12∙161+15∙160 = 1∙256+12∙16+15∙1 = 256+192+15 = 46310
got It: 1CF16 =46310
Translate the number 46310 в octal like this:
the Integer part of the number is divided by the base of the new number system:
463 | 8 | | |
-456 | 57 | 8 | |
7 | -56 | 7 | |
| 1 | | |
|
the result of the conversion was:
46310 = 7178
answer: 1CF16 = 7178
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
1CF16 = 1 C F = 1(=0001) C(=1100) F(=1111) = 1110011112
answer: 1CF16 = 1110011112
let\'s make a direct translation from binary to post-binary like this:
1110011112 = 111 001 111 = 111(=7) 001(=1) 111(=7) = 7178
answer: 1CF16 = 7178