This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
0f3516 = 0 f 3 5 = 0(=0000) f(=1111) 3(=0011) 5(=0101) = 1111001101012
answer: 0f3516 = 1111001101012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙163+15∙162+3∙161+5∙160 = 0∙4096+15∙256+3∙16+5∙1 = 0+3840+48+5 = 389310
got It: 0f3516 =389310
Translate the number 389310 в binary like this:
the Integer part of the number is divided by the base of the new number system:
3893 | 2 | | | | | | | | | | | |
-3892 | 1946 | 2 | | | | | | | | | | |
1 | -1946 | 973 | 2 | | | | | | | | | |
| 0 | -972 | 486 | 2 | | | | | | | | |
| | 1 | -486 | 243 | 2 | | | | | | | |
| | | 0 | -242 | 121 | 2 | | | | | | |
| | | | 1 | -120 | 60 | 2 | | | | | |
| | | | | 1 | -60 | 30 | 2 | | | | |
| | | | | | 0 | -30 | 15 | 2 | | | |
| | | | | | | 0 | -14 | 7 | 2 | | |
| | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | 1 | | |
|
the result of the conversion was:
389310 = 1111001101012
answer: 0f3516 = 1111001101012