This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
11111111.000111002 = 1111 1111. 0001 1100 = 1111(=F) 1111(=F). 0001(=1) 1100(=C) = FF.1C16
the Final answer: 11111111.000111002 = FF.1C16
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙27+1∙26+1∙25+1∙24+1∙23+1∙22+1∙21+1∙20+0∙2-1+0∙2-2+0∙2-3+1∙2-4+1∙2-5+1∙2-6+0∙2-7+0∙2-8 = 1∙128+1∙64+1∙32+1∙16+1∙8+1∙4+1∙2+1∙1+0∙0.5+0∙0.25+0∙0.125+1∙0.0625+1∙0.03125+1∙0.015625+0∙0.0078125+0∙0.00390625 = 128+64+32+16+8+4+2+1+0+0+0+0.0625+0.03125+0.015625+0+0 = 255.10937510
got It: 11111111.000111002 =255.10937510
Translate the number 255.10937510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
255 | 16 | |
-240 | F | |
F | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 109375*16 |
1 | .75*16 |
C | .0*16 |
the result of the conversion was:
255.10937510 = FF.1C16
the Final answer: 11111111.000111002 = FF.1C16