This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
12A616 = 1 2 A 6 = 1(=0001) 2(=0010) A(=1010) 6(=0110) = 10010101001102
answer: 12A616 = 10010101001102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙163+2∙162+10∙161+6∙160 = 1∙4096+2∙256+10∙16+6∙1 = 4096+512+160+6 = 477410
got It: 12A616 =477410
Translate the number 477410 в binary like this:
the Integer part of the number is divided by the base of the new number system:
4774 | 2 | | | | | | | | | | | | |
-4774 | 2387 | 2 | | | | | | | | | | | |
0 | -2386 | 1193 | 2 | | | | | | | | | | |
| 1 | -1192 | 596 | 2 | | | | | | | | | |
| | 1 | -596 | 298 | 2 | | | | | | | | |
| | | 0 | -298 | 149 | 2 | | | | | | | |
| | | | 0 | -148 | 74 | 2 | | | | | | |
| | | | | 1 | -74 | 37 | 2 | | | | | |
| | | | | | 0 | -36 | 18 | 2 | | | | |
| | | | | | | 1 | -18 | 9 | 2 | | | |
| | | | | | | | 0 | -8 | 4 | 2 | | |
| | | | | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | 0 | | |
|
the result of the conversion was:
477410 = 10010101001102
answer: 12A616 = 10010101001102