This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
101111.1002 = 101 111. 100 = 101(=5) 111(=7). 100(=4) = 57.48
answer: 101111.102 = 57.48
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙25+0∙24+1∙23+1∙22+1∙21+1∙20+1∙2-1+0∙2-2+0∙2-3 = 1∙32+0∙16+1∙8+1∙4+1∙2+1∙1+1∙0.5+0∙0.25+0∙0.125 = 32+0+8+4+2+1+0.5+0+0 = 47.510
got It: 101111.1002 =47.510
Translate the number 47.510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
47 | 8 | |
-40 | 5 | |
7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 5*8 |
4 | .0*8 |
the result of the conversion was:
47.510 = 57.48
answer: 101111.102 = 57.48