This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
C516 = C 5 = C(=1100) 5(=0101) = 110001012
answer: C516 = 110001012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
12∙161+5∙160 = 12∙16+5∙1 = 192+5 = 19710
got It: C516 =19710
Translate the number 19710 в binary like this:
the Integer part of the number is divided by the base of the new number system:
197 | 2 | | | | | | | |
-196 | 98 | 2 | | | | | | |
1 | -98 | 49 | 2 | | | | | |
| 0 | -48 | 24 | 2 | | | | |
| | 1 | -24 | 12 | 2 | | | |
| | | 0 | -12 | 6 | 2 | | |
| | | | 0 | -6 | 3 | 2 | |
| | | | | 0 | -2 | 1 | |
| | | | | | 1 | | |
|
the result of the conversion was:
19710 = 110001012
answer: C516 = 110001012