This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
100101.1001002 = 100 101. 100 100 = 100(=4) 101(=5). 100(=4) 100(=4) = 45.448
answer: 100101.10012 = 45.448
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙25+0∙24+0∙23+1∙22+0∙21+1∙20+1∙2-1+0∙2-2+0∙2-3+1∙2-4+0∙2-5+0∙2-6 = 1∙32+0∙16+0∙8+1∙4+0∙2+1∙1+1∙0.5+0∙0.25+0∙0.125+1∙0.0625+0∙0.03125+0∙0.015625 = 32+0+0+4+0+1+0.5+0+0+0.0625+0+0 = 37.562510
got It: 100101.1001002 =37.562510
Translate the number 37.562510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
37 | 8 | |
-32 | 4 | |
5 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 5625*8 |
4 | .5*8 |
4 | .0*8 |
the result of the conversion was:
37.562510 = 45.448
answer: 100101.10012 = 45.448