This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
010111.1011002 = 010 111. 101 100 = 010(=2) 111(=7). 101(=5) 100(=4) = 27.548
answer: 10111.1011002 = 27.548
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙25+1∙24+0∙23+1∙22+1∙21+1∙20+1∙2-1+0∙2-2+1∙2-3+1∙2-4+0∙2-5+0∙2-6 = 0∙32+1∙16+0∙8+1∙4+1∙2+1∙1+1∙0.5+0∙0.25+1∙0.125+1∙0.0625+0∙0.03125+0∙0.015625 = 0+16+0+4+2+1+0.5+0+0.125+0.0625+0+0 = 23.687510
got It: 010111.1011002 =23.687510
Translate the number 23.687510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
23 | 8 | |
-16 | 2 | |
7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 6875*8 |
5 | .5*8 |
4 | .0*8 |
the result of the conversion was:
23.687510 = 27.548
answer: 10111.1011002 = 27.548