This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
0001101001112 = 000 110 100 111 = 000(=0) 110(=6) 100(=4) 111(=7) = 06478
answer: 0001101001112 = 06478
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+0∙210+0∙29+1∙28+1∙27+0∙26+1∙25+0∙24+0∙23+1∙22+1∙21+1∙20 = 0∙2048+0∙1024+0∙512+1∙256+1∙128+0∙64+1∙32+0∙16+0∙8+1∙4+1∙2+1∙1 = 0+0+0+256+128+0+32+0+0+4+2+1 = 42310
got It: 0001101001112 =42310
Translate the number 42310 в octal like this:
the Integer part of the number is divided by the base of the new number system:
423 | 8 | | |
-416 | 52 | 8 | |
7 | -48 | 6 | |
| 4 | | |
|
the result of the conversion was:
42310 = 6478
answer: 0001101001112 = 6478