This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001110101.1001002 = 001 110 101. 100 100 = 001(=1) 110(=6) 101(=5). 100(=4) 100(=4) = 165.448
answer: 1110101.10012 = 165.448
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+0∙27+1∙26+1∙25+1∙24+0∙23+1∙22+0∙21+1∙20+1∙2-1+0∙2-2+0∙2-3+1∙2-4+0∙2-5+0∙2-6 = 0∙256+0∙128+1∙64+1∙32+1∙16+0∙8+1∙4+0∙2+1∙1+1∙0.5+0∙0.25+0∙0.125+1∙0.0625+0∙0.03125+0∙0.015625 = 0+0+64+32+16+0+4+0+1+0.5+0+0+0.0625+0+0 = 117.562510
got It: 001110101.1001002 =117.562510
Translate the number 117.562510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
117 | 8 | | |
-112 | 14 | 8 | |
5 | -8 | 1 | |
| 6 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 5625*8 |
4 | .5*8 |
4 | .0*8 |
the result of the conversion was:
117.562510 = 165.448
answer: 1110101.10012 = 165.448