This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
011101001.1100102 = 011 101 001. 110 010 = 011(=3) 101(=5) 001(=1). 110(=6) 010(=2) = 351.628
answer: 011101001.1100102 = 351.628
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+1∙26+1∙25+0∙24+1∙23+0∙22+0∙21+1∙20+1∙2-1+1∙2-2+0∙2-3+0∙2-4+1∙2-5+0∙2-6 = 0∙256+1∙128+1∙64+1∙32+0∙16+1∙8+0∙4+0∙2+1∙1+1∙0.5+1∙0.25+0∙0.125+0∙0.0625+1∙0.03125+0∙0.015625 = 0+128+64+32+0+8+0+0+1+0.5+0.25+0+0+0.03125+0 = 233.7812510
got It: 011101001.1100102 =233.7812510
Translate the number 233.7812510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
233 | 8 | | |
-232 | 29 | 8 | |
1 | -24 | 3 | |
| 5 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 78125*8 |
6 | .25*8 |
2 | .0*8 |
the result of the conversion was:
233.7812510 = 351.628
answer: 011101001.1100102 = 351.628