This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
11∙162+11∙161+10∙160 = 11∙256+11∙16+10∙1 = 2816+176+10 = 300210
got It: BBA16 =300210
Translate the number 300210 в octal like this:
the Integer part of the number is divided by the base of the new number system:
3002 | 8 | | | |
-3000 | 375 | 8 | | |
2 | -368 | 46 | 8 | |
| 7 | -40 | 5 | |
| | 6 | | |
|
the result of the conversion was:
300210 = 56728
answer: BBA16 = 56728
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
BBA16 = B B A = B(=1011) B(=1011) A(=1010) = 1011101110102
answer: BBA16 = 1011101110102
let\'s make a direct translation from binary to post-binary like this:
1011101110102 = 101 110 111 010 = 101(=5) 110(=6) 111(=7) 010(=2) = 56728
answer: BBA16 = 56728