This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
0∙160+3∙16-1+5∙16-2 = 0∙1+3∙0.0625+5∙0.00390625 = 0+0.1875+0.01953125 = 0.2070312510
got It: 0.3516 =0.2070312510
Translate the number 0.2070312510 в octal like this:
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 20703125*8 |
1 | .65625*8 |
5 | .25*8 |
2 | .0*8 |
the result of the conversion was:
0.2070312510 = 0.1528
the Final answer: 0.3516 = 0.1528
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
0.3516 = 0. 3 5 = 0(=0000). 3(=0011) 5(=0101) = .001101012
the Final answer: 0.3516 = .001101012
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
.0011010102 = . 001 101 010 = . 001(=1) 101(=5) 010(=2) = .1528
the Final answer: 0.3516 = .1528