This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
245816 = 2 4 5 8 = 2(=0010) 4(=0100) 5(=0101) 8(=1000) = 100100010110002
answer: 245816 = 100100010110002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
2∙163+4∙162+5∙161+8∙160 = 2∙4096+4∙256+5∙16+8∙1 = 8192+1024+80+8 = 930410
got It: 245816 =930410
Translate the number 930410 в binary like this:
the Integer part of the number is divided by the base of the new number system:
9304 | 2 | | | | | | | | | | | | | |
-9304 | 4652 | 2 | | | | | | | | | | | | |
0 | -4652 | 2326 | 2 | | | | | | | | | | | |
| 0 | -2326 | 1163 | 2 | | | | | | | | | | |
| | 0 | -1162 | 581 | 2 | | | | | | | | | |
| | | 1 | -580 | 290 | 2 | | | | | | | | |
| | | | 1 | -290 | 145 | 2 | | | | | | | |
| | | | | 0 | -144 | 72 | 2 | | | | | | |
| | | | | | 1 | -72 | 36 | 2 | | | | | |
| | | | | | | 0 | -36 | 18 | 2 | | | | |
| | | | | | | | 0 | -18 | 9 | 2 | | | |
| | | | | | | | | 0 | -8 | 4 | 2 | | |
| | | | | | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
930410 = 100100010110002
answer: 245816 = 100100010110002