This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
110011.1110002 = 110 011. 111 000 = 110(=6) 011(=3). 111(=7) 000(=0) = 63.708
answer: 110011.111002 = 63.708
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙25+1∙24+0∙23+0∙22+1∙21+1∙20+1∙2-1+1∙2-2+1∙2-3+0∙2-4+0∙2-5+0∙2-6 = 1∙32+1∙16+0∙8+0∙4+1∙2+1∙1+1∙0.5+1∙0.25+1∙0.125+0∙0.0625+0∙0.03125+0∙0.015625 = 32+16+0+0+2+1+0.5+0.25+0.125+0+0+0 = 51.87510
got It: 110011.1110002 =51.87510
Translate the number 51.87510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
51 | 8 | |
-48 | 6 | |
3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 875*8 |
7 | .0*8 |
the result of the conversion was:
51.87510 = 63.78
answer: 110011.111002 = 63.78