This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0111110112 = 011 111 011 = 011(=3) 111(=7) 011(=3) = 3738
the Final answer: 111110112 = 3738
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+1∙26+1∙25+1∙24+1∙23+0∙22+1∙21+1∙20 = 0∙256+1∙128+1∙64+1∙32+1∙16+1∙8+0∙4+1∙2+1∙1 = 0+128+64+32+16+8+0+2+1 = 25110
got It: 0111110112 =25110
Translate the number 25110 в octal like this:
the Integer part of the number is divided by the base of the new number system:
251 | 8 | | |
-248 | 31 | 8 | |
3 | -24 | 3 | |
| 7 | | |
|
the result of the conversion was:
25110 = 3738
the Final answer: 111110112 = 3738