This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0000011110112 = 0000 0111 1011 = 0000(=0) 0111(=7) 1011(=B) = 07B16
answer: 0000011110112 = 07B16
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+0∙210+0∙29+0∙28+0∙27+1∙26+1∙25+1∙24+1∙23+0∙22+1∙21+1∙20 = 0∙2048+0∙1024+0∙512+0∙256+0∙128+1∙64+1∙32+1∙16+1∙8+0∙4+1∙2+1∙1 = 0+0+0+0+0+64+32+16+8+0+2+1 = 12310
got It: 0000011110112 =12310
Translate the number 12310 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
123 | 16 | |
-112 | 7 | |
B | | |
|
the result of the conversion was:
12310 = 7B16
answer: 0000011110112 = 7B16