This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
010111012 = 0101 1101 = 0101(=5) 1101(=D) = 5D16
the Final answer: 010111012 = 5D16
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙27+1∙26+0∙25+1∙24+1∙23+1∙22+0∙21+1∙20 = 0∙128+1∙64+0∙32+1∙16+1∙8+1∙4+0∙2+1∙1 = 0+64+0+16+8+4+0+1 = 9310
got It: 010111012 =9310
Translate the number 9310 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
93 | 16 | |
-80 | 5 | |
D | | |
|
the result of the conversion was:
9310 = 5D16
the Final answer: 010111012 = 5D16