This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
0101100110102 = 010 110 011 010 = 010(=2) 110(=6) 011(=3) 010(=2) = 26328
answer: 0101100110102 = 26328
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+1∙210+0∙29+1∙28+1∙27+0∙26+0∙25+1∙24+1∙23+0∙22+1∙21+0∙20 = 0∙2048+1∙1024+0∙512+1∙256+1∙128+0∙64+0∙32+1∙16+1∙8+0∙4+1∙2+0∙1 = 0+1024+0+256+128+0+0+16+8+0+2+0 = 143410
got It: 0101100110102 =143410
Translate the number 143410 в octal like this:
the Integer part of the number is divided by the base of the new number system:
1434 | 8 | | | |
-1432 | 179 | 8 | | |
2 | -176 | 22 | 8 | |
| 3 | -16 | 2 | |
| | 6 | | |
|
the result of the conversion was:
143410 = 26328
answer: 0101100110102 = 26328