This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
2∙81+0∙80+6∙8-1 = 2∙8+0∙1+6∙0.125 = 16+0+0.75 = 16.7510
got It: 20.68 =16.7510
Translate the number 16.7510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
16 | 16 | |
-16 | 1 | |
0 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 75*16 |
C | .0*16 |
the result of the conversion was:
16.7510 = 10.C16
answer: 20.68 = 10.C16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
20.68 = 2 0. 6 = 2(=010) 0(=000). 6(=110) = 010000.1102
answer: 20.68 = 10000.112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
00010000.11002 = 0001 0000. 1100 = 0001(=1) 0000(=0). 1100(=C) = 10.C16
answer: 00010000.11008 = 10.C16