This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
15∙163+14∙162+10∙161+6∙160 = 15∙4096+14∙256+10∙16+6∙1 = 61440+3584+160+6 = 6519010
got It: fea616 =6519010
Translate the number 6519010 в octal like this:
the Integer part of the number is divided by the base of the new number system:
65190 | 8 | | | | | |
-65184 | 8148 | 8 | | | | |
6 | -8144 | 1018 | 8 | | | |
| 4 | -1016 | 127 | 8 | | |
| | 2 | -120 | 15 | 8 | |
| | | 7 | -8 | 1 | |
| | | | 7 | | |
|
the result of the conversion was:
6519010 = 1772468
answer: fea616 = 1772468
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
fea616 = f e a 6 = f(=1111) e(=1110) a(=1010) 6(=0110) = 11111110101001102
answer: fea616 = 11111110101001102
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011111110101001102 = 001 111 111 010 100 110 = 001(=1) 111(=7) 111(=7) 010(=2) 100(=4) 110(=6) = 1772468
answer: fea616 = 1772468