This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0110101102 = 011 010 110 = 011(=3) 010(=2) 110(=6) = 3268
answer: 110101102 = 3268
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+1∙26+0∙25+1∙24+0∙23+1∙22+1∙21+0∙20 = 0∙256+1∙128+1∙64+0∙32+1∙16+0∙8+1∙4+1∙2+0∙1 = 0+128+64+0+16+0+4+2+0 = 21410
got It: 0110101102 =21410
Translate the number 21410 в octal like this:
the Integer part of the number is divided by the base of the new number system:
214 | 8 | | |
-208 | 26 | 8 | |
6 | -24 | 3 | |
| 2 | | |
|
the result of the conversion was:
21410 = 3268
answer: 110101102 = 3268