This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001011.1010002 = 001 011. 101 000 = 001(=1) 011(=3). 101(=5) 000(=0) = 13.508
answer: 1011.10102 = 13.508
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙25+0∙24+1∙23+0∙22+1∙21+1∙20+1∙2-1+0∙2-2+1∙2-3+0∙2-4+0∙2-5+0∙2-6 = 0∙32+0∙16+1∙8+0∙4+1∙2+1∙1+1∙0.5+0∙0.25+1∙0.125+0∙0.0625+0∙0.03125+0∙0.015625 = 0+0+8+0+2+1+0.5+0+0.125+0+0+0 = 11.62510
got It: 001011.1010002 =11.62510
Translate the number 11.62510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
11 | 8 | |
-8 | 1 | |
3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 625*8 |
5 | .0*8 |
the result of the conversion was:
11.62510 = 13.58
answer: 1011.10102 = 13.58