This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
088216 = 0 8 8 2 = 0(=0000) 8(=1000) 8(=1000) 2(=0010) = 1000100000102
answer: 088216 = 1000100000102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙163+8∙162+8∙161+2∙160 = 0∙4096+8∙256+8∙16+2∙1 = 0+2048+128+2 = 217810
got It: 088216 =217810
Translate the number 217810 в binary like this:
the Integer part of the number is divided by the base of the new number system:
2178 | 2 | | | | | | | | | | | |
-2178 | 1089 | 2 | | | | | | | | | | |
0 | -1088 | 544 | 2 | | | | | | | | | |
| 1 | -544 | 272 | 2 | | | | | | | | |
| | 0 | -272 | 136 | 2 | | | | | | | |
| | | 0 | -136 | 68 | 2 | | | | | | |
| | | | 0 | -68 | 34 | 2 | | | | | |
| | | | | 0 | -34 | 17 | 2 | | | | |
| | | | | | 0 | -16 | 8 | 2 | | | |
| | | | | | | 1 | -8 | 4 | 2 | | |
| | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | 0 | | |
|
the result of the conversion was:
217810 = 1000100000102
answer: 088216 = 1000100000102