This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
6∙163+15∙162+5∙161+9∙160+3∙16-1+13∙16-2 = 6∙4096+15∙256+5∙16+9∙1+3∙0.0625+13∙0.00390625 = 24576+3840+80+9+0.1875+0.05078125 = 28505.2382812510
got It: 6F59.3D16 =28505.2382812510
Translate the number 28505.2382812510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
28505 | 8 | | | | |
-28504 | 3563 | 8 | | | |
1 | -3560 | 445 | 8 | | |
| 3 | -440 | 55 | 8 | |
| | 5 | -48 | 6 | |
| | | 7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 23828125*8 |
1 | .90625*8 |
7 | .25*8 |
2 | .0*8 |
the result of the conversion was:
28505.2382812510 = 67531.1728
answer: 6F59.3D16 = 67531.1728
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
6F59.3D16 = 6 F 5 9. 3 D = 6(=0110) F(=1111) 5(=0101) 9(=1001). 3(=0011) D(=1101) = 110111101011001.001111012
answer: 6F59.3D16 = 110111101011001.001111012
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
110111101011001.0011110102 = 110 111 101 011 001. 001 111 010 = 110(=6) 111(=7) 101(=5) 011(=3) 001(=1). 001(=1) 111(=7) 010(=2) = 67531.1728
answer: 6F59.3D16 = 67531.1728