This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
011111011.0102 = 011 111 011. 010 = 011(=3) 111(=7) 011(=3). 010(=2) = 373.28
answer: 11111011.012 = 373.28
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+1∙26+1∙25+1∙24+1∙23+0∙22+1∙21+1∙20+0∙2-1+1∙2-2+0∙2-3 = 0∙256+1∙128+1∙64+1∙32+1∙16+1∙8+0∙4+1∙2+1∙1+0∙0.5+1∙0.25+0∙0.125 = 0+128+64+32+16+8+0+2+1+0+0.25+0 = 251.2510
got It: 011111011.0102 =251.2510
Translate the number 251.2510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
251 | 8 | | |
-248 | 31 | 8 | |
3 | -24 | 3 | |
| 7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 25*8 |
2 | .0*8 |
the result of the conversion was:
251.2510 = 373.28
answer: 11111011.012 = 373.28