This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
1100012 = 110 001 = 110(=6) 001(=1) = 618
answer: 1100012 = 618
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙25+1∙24+0∙23+0∙22+0∙21+1∙20 = 1∙32+1∙16+0∙8+0∙4+0∙2+1∙1 = 32+16+0+0+0+1 = 4910
got It: 1100012 =4910
Translate the number 4910 в octal like this:
the Integer part of the number is divided by the base of the new number system:
49 | 8 | |
-48 | 6 | |
1 | | |
|
the result of the conversion was:
4910 = 618
answer: 1100012 = 618