This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
1DDD16 = 1 D D D = 1(=0001) D(=1101) D(=1101) D(=1101) = 11101110111012
answer: 1DDD16 = 11101110111012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙163+13∙162+13∙161+13∙160 = 1∙4096+13∙256+13∙16+13∙1 = 4096+3328+208+13 = 764510
got It: 1DDD16 =764510
Translate the number 764510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
7645 | 2 | | | | | | | | | | | | |
-7644 | 3822 | 2 | | | | | | | | | | | |
1 | -3822 | 1911 | 2 | | | | | | | | | | |
| 0 | -1910 | 955 | 2 | | | | | | | | | |
| | 1 | -954 | 477 | 2 | | | | | | | | |
| | | 1 | -476 | 238 | 2 | | | | | | | |
| | | | 1 | -238 | 119 | 2 | | | | | | |
| | | | | 0 | -118 | 59 | 2 | | | | | |
| | | | | | 1 | -58 | 29 | 2 | | | | |
| | | | | | | 1 | -28 | 14 | 2 | | | |
| | | | | | | | 1 | -14 | 7 | 2 | | |
| | | | | | | | | 0 | -6 | 3 | 2 | |
| | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | 1 | | |
|
the result of the conversion was:
764510 = 11101110111012
answer: 1DDD16 = 11101110111012