This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
4∙161+13∙160+2∙16-1+1∙16-2 = 4∙16+13∙1+2∙0.0625+1∙0.00390625 = 64+13+0.125+0.00390625 = 77.1289062510
got It: 4D.2116 =77.1289062510
Translate the number 77.1289062510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
77 | 8 | | |
-72 | 9 | 8 | |
5 | -8 | 1 | |
| 1 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 12890625*8 |
1 | .03125*8 |
0 | .25*8 |
2 | .0*8 |
the result of the conversion was:
77.1289062510 = 115.1028
answer: 4D.2116 = 115.1028
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
4D.2116 = 4 D. 2 1 = 4(=0100) D(=1101). 2(=0010) 1(=0001) = 1001101.001000012
answer: 4D.2116 = 1001101.001000012
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001001101.0010000102 = 001 001 101. 001 000 010 = 001(=1) 001(=1) 101(=5). 001(=1) 000(=0) 010(=2) = 115.1028
answer: 4D.2116 = 115.1028