This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
110110.1101102 = 110 110. 110 110 = 110(=6) 110(=6). 110(=6) 110(=6) = 66.668
answer: 110110.1101102 = 66.668
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙25+1∙24+0∙23+1∙22+1∙21+0∙20+1∙2-1+1∙2-2+0∙2-3+1∙2-4+1∙2-5+0∙2-6 = 1∙32+1∙16+0∙8+1∙4+1∙2+0∙1+1∙0.5+1∙0.25+0∙0.125+1∙0.0625+1∙0.03125+0∙0.015625 = 32+16+0+4+2+0+0.5+0.25+0+0.0625+0.03125+0 = 54.8437510
got It: 110110.1101102 =54.8437510
Translate the number 54.8437510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
54 | 8 | |
-48 | 6 | |
6 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 84375*8 |
6 | .75*8 |
6 | .0*8 |
the result of the conversion was:
54.8437510 = 66.668
answer: 110110.1101102 = 66.668