This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0110010012 = 011 001 001 = 011(=3) 001(=1) 001(=1) = 3118
answer: 110010012 = 3118
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+1∙26+0∙25+0∙24+1∙23+0∙22+0∙21+1∙20 = 0∙256+1∙128+1∙64+0∙32+0∙16+1∙8+0∙4+0∙2+1∙1 = 0+128+64+0+0+8+0+0+1 = 20110
got It: 0110010012 =20110
Translate the number 20110 в octal like this:
the Integer part of the number is divided by the base of the new number system:
201 | 8 | | |
-200 | 25 | 8 | |
1 | -24 | 3 | |
| 1 | | |
|
the result of the conversion was:
20110 = 3118
answer: 110010012 = 3118