This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
6∙82+2∙81+3∙80 = 6∙64+2∙8+3∙1 = 384+16+3 = 40310
got It: 6238 =40310
Translate the number 40310 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
403 | 16 | | |
-400 | 25 | 16 | |
3 | -16 | 1 | |
| 9 | | |
|
the result of the conversion was:
40310 = 19316
answer: 6238 = 19316
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
6238 = 6 2 3 = 6(=110) 2(=010) 3(=011) = 1100100112
answer: 6238 = 1100100112
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0001100100112 = 0001 1001 0011 = 0001(=1) 1001(=9) 0011(=3) = 19316
answer: 0001100100118 = 19316